Exercicis de matemàtiques/Combinades

Quines operacions podem fer servir perquè tres números iguals donin un resultat?

Resultat 1

$1\cdot 1\cdot 1=1\$

$2^{2-2}=1\$

$3^{3-3}=1\$

$4^{4-4}=1\$

$5^{5-5}=1\$

$6^{6-6}=1\$

$7^{7-7}=1\$

$8^{8-8}=1\$

$9^{9-9}=1\$

Resultat 2

$1\cdot 1+1=2\$

$2+2-2=2\$

$3-3:3=2\$

${\sqrt {4}}+{\sqrt {4}}-{\sqrt {4}}=2\$

${\sqrt {5-5:5}}=2\$

$(6+6):6=2\$

$(7+7):7=2\$

$(8+8):8=2\$

$(9+9):9=2\$

Resultat 3

$1+1+1=3\$

$2+2:2=3\$

$3\cdot 3:3=3\$

$4-4:4=3\$

$555=3\$

$666=3\$

$777=3\$

${\sqrt[{3}]{8}}+8:8=3\$

${\sqrt {9}}+{\sqrt {9}}-{\sqrt {9}}=3\$

Resultat 4

$111=4\$

${\sqrt {2*2}}+2=4\$

$3+3:3=4\$

$4+4-4=4\$

$5-5:5=4\$

$666=4\$

$777=4\$

${\sqrt {\sqrt[{3}]{8\cdot 8}}}+{\sqrt[{3}]{8}}=4\$

${\sqrt {9}}+9:9=4\$

Resultat 5

$111=5\$

$222=5\$

$3!-3:3=5\$

$4+4:4=5\$

$5+5-5=5\$

$6-6:6=5\$

$777=5\$

$888=5\$

$999=5\$

Resultat 6

$(1+1+1)!=6\$

$2+2+2=6\$

$3\cdot 3-3=6\$

${\sqrt {4}}+{\sqrt {4}}+{\sqrt {4}}=6\$

$5+5:5=6\$

$6+6-6=6\$

$7-7:7=6\$

${\sqrt[{3}]{8}}+{\sqrt[{3}]{8}}+{\sqrt[{3}]{8}}=6\$

${\sqrt {9*9}}-{\sqrt {9}}=6\$

Resultat 7

$111=7\$

$222=7\$

$3!+3:3=7\$

$(4!+4):4=7\$

$555=7\$

$6+6:6=7\$

$7+7-7=7\$

$8-8:8=7\$

$999=7\$

Resultat 8

$111=8\$

$2\cdot 2\cdot 2=8\$

$333=8\$

${\sqrt {4\cdot 4}}+4=8\$

$555=8\$

$666=8\$

$7+7:7=8\$

$8+8-8=8\$

$9-9:9=8\$

Resultat 9

$111=9\$

$222=9\$

$3+3+3=9\$

$444=9\$

$555=9\$

$666=9\$

$777=9\$

$8+8:8=9\$

$9+9-9=9\$